Java 8 Best way to create IntStream from input

Question

I have an input (STDIN)

0 0 1 2 1

and I want to create a stream from it in the easiest way.

I created a stream by reading one for each integer and storing them in an ArrayList. From there, I just had to use .stream (). Reduce () to make it work.

What I want is a possible way to create a stream directly from input

I tried to adapt this code:

ByteArrayInputStream inputStream = new ByteArrayInputStream(bytes); IntStream is2 = IntStream.generate(inputStream::read).limit(inputStream.available()); 

using the DataInputStream and readInt () method

 DataInputStream dis = new DataInputStream(System.in); IntStream is2 = IntStream.generate(dis::readInt).limit(5);//later : dis.available() instead of 5 

but it does not work. I have incompatible thrown IOException types for the generate function.

Can I do it? Or is there another way to convert input to stream

my reduction function to be applied,

 reduce( (x , y) -> x ^ y) 

I already did this on an ArrayList quite easily by doing

 list.stream().reduce( (x , y) -> x ^ y); 

Decision

I tried using this with a scanner to do this job, but to no avail, and now I managed to get it to work

 Scanner sc = new Scanner(System.in); int oi = Stream.of(sc.nextLine().split(" ")) .mapToInt(Integer::parseInt) .reduce( (x , y) -> x ^ y).getAsInt(); System.out.println(oi); 

I do not understand why this did not work in the beginning

Answer 1

Decision

 Scanner sc = new Scanner(System.in); int oi = Stream.of(sc.nextLine().split(" ")) .mapToInt(Integer::parseInt) .reduce( (x , y) -> x ^ y).getAsInt(); System.out.println(oi); 

Answer 2

Using the @Holger recommendation using splitAsStream instead of Stream.of

 int solution2 = Pattern.compile("\\s+").splitAsStream(sc.nextLine()) .mapToInt(Integer::parseInt) .reduce( (x , y) -> x ^ y).getAsInt();; System.out.println(solution2);