How to add a string to a string array in C

Question

So, I got to know C again, and this concept got me stuck especially.

The goal is to create a dynamically distributed array of strings. I did this by first creating a null array and allocating the appropriate amount of space for each row entered. The only problem is when I try to actually add a line, I get a seg error! I can’t understand why, I suspect that this is due to an incorrect allocation, since I do not see anything wrong with my strcpy function.

I reviewed this site in detail for an answer, and I found help, but cannot close the deal. Any help you can provide would be greatly appreciated!

#include <stdio.h> #include <string.h> #include <stdlib.h> int main() { int count = 0; //array index counter char *word; //current word char **array = NULL; char *term = "q"; //termination character char *prnt = "print"; while (strcmp(term, word) != 0) { printf("Enter a string. Enter q to end. Enter print to print array\n"); // fgets(word, sizeof(word), stdin); adds a newline character to the word. wont work in this case scanf("%s", word); //printf("word: %s\nterm: %s\n",word, term); if (strcmp(term, word) == 0) { printf("Terminate\n"); } else if (strcmp(prnt, word) == 0) { printf("Enumerate\n"); int i; for (i=0; i<count; i++) { printf("Slot %d: %s\n",i, array[i]); } } else { printf("String added to array\n"); count++; array = (char**)realloc(array, (count+1)*sizeof(*array)); array[count-1] = (char*)malloc(sizeof(word)); strcpy(array[count-1], word); } } return ; } 

Answer 1

word has no allocated memory. Your program in its current form tramples on unallocated memory as users enter words into your program.

You must indicate how large your input will be and allocate the input buffer as follows:

 char word[80]; // for 80 char max input per entry