Elegantly delete part of a string after the last occurrence of a character

Question

Suppose I want to delete everything after the last '*' (for example) in a string. Knowing that for this line I can accept the following:

• It will ALWAYS contain '*'
• MAY contain more than one * *
• It will NEVER start or end with the '*' symbol

What is the cleanest and / or shortest way to remove all of the past from the last '*', plus myself, only with base libraries?

Answer 1

Given your assumptions:

s.erase(s.rfind('*')); 

Without the assumption that it contains at least one * :

 auto pos = s.rfind('*'); if (pos != std::string::npos) { s.erase(pos); }