How to get the name of the Generic Func <T> method passed to the method

Question

I am trying to get the method name of a function passed to an object using .Net closure as follows:

Method signature

public IEnumerable<T> GetData<T>(Func<IEnumerable<T>> WebServiceCallback) where T : class { // either gets me '<LoadData>b__3' var a = nrdsWebServiceCallback.Method.Name; var b = nrdsWebServiceCallback.GetInvocationList(); return WebServiceCallback(); } 

I call it this way:

 SessionStateService.Labs = CacheManager.GetData(() => WCFService.GetLabs(SessionStateService.var1, SessionStateService.var2)); 

View "b__3" instead of WCFServce.GetLabs (..) etc.

Answer 1

You are looking at the name of the lambda expression (generated by the compiler) instead of the name of the method called inside the lambda.

You should use <Expression<Func<T>> instead of Func<T> . Expressions can be analyzed and analyzed.

Try

 public IEnumerable<T> GetData<T>(Expression<Func<IEnumerable<T>>> callbackExpression) where T : class { var methodCall = callbackExpression.Body as MethodCallExpression; if(methodCall != null) { string methodName = methodCall.Method.Name; } return callbackExpression.Compile()(); } 

Answer 2

What is actually passed into your function is the anonymous lambda function ( () => WCFService.Etc ), so you see the actual method name - <LoadData>b__3 - this is the auto- <LoadData>b__3 name of the anonymous method.

What you really want is a method called inside the called method. To do this, you need to delve into the expression. Instead of Func<IEnumerable<T>> define your parameter as Expression<Func<IEnumerable<T>>> and call this code:

 var body = nrdsWebServiceCallback.Body as MethodCallExpression; if (body != null) Console.WriteLine(body.Method.DeclaringType.Name + "." + body.Method.Name);