Show exact matches only with GREP

Question

How can I display all tasks that ended only with OK?

When I try to execute the command below, it shows both OK and NOTOK, since both have "OK"

ctmpsm -listall application | grep OK 

Answer 1

You need a more specific expression. Try grep " OK$" or grep "[0-9]* OK" . You want to select a template that matches what you want, but doesn't match what you don’t want. This template will depend on how your content will look like all the content.

You can also do: grep -w "OK" , which will only match the whole word "OK", for example, "1 OK", but will not match "1OK" or "OKFINE".

 $ cat test.txt | grep -w "OK" 1 OK 2 OK 4 OK 

Answer 2

This may work for you.

 grep -E '(^|\s)OK($|\s)' 

Answer 3

Try the following:

 Alex Misuno@hp4530s ~ $ cat test.txt 1 OK 2 OK 3 NOTOK 4 OK 5 NOTOK Alex Misuno@hp4530s ~ $ cat test.txt | grep ".* OK$" 1 OK 2 OK 4 OK 

Answer 4

This worked for me :

 grep "\bsearch_word\b" text_file > output.txt ## \b indicates boundaries. This is much faster. 

or,

 grep -w "search_word" text_file > output.txt 

Answer 5

try the following: grep -P '^ (tomcat !?)' tst1.txt

It will search for a specific word in the txt file. Here we are trying to find the word 'tomcat'

Answer 6

^ marks the beginning of a line, and $ marks the end of a line. This will only return exact "OK" matches.

(This also works with double quotes, if that is your preference.)

 grep '^OK$' 

Answer 7

Try the command below because it works fine:

 grep -ow "yourstring" crosscheck:- 

Delete the instance of the word from the file, then re-run this command and it should display an empty result.