Could not find web.xml in netbeans 7.0.1

Question

I want to upload a file to a server for which I am writing a servlet program. The location of the directory where the document will be loaded should be selected from the parameter in web.xml. I have not used web.xml before and I only know that it makes entries for each servlet. I can not see this file in my web application project, which I do in netbeans. Please help me with this. Thanks.

Answer 1

It should be located in the YOURPROJECT\web\WEB-INF folder, so the full path will be: YOURPROJECT\web\WEB-INF\web.xml

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EDIT (August 21, 2015)

Got downvote with duffymo comment that my answer is incorrect.

And I decided to illustrate my answer with step by step pictures in order to avoid misunderstandings.

I am going to illustrate Netbeans behavior on Linux (Ubuntu) and Windows (Windows 7) operating systems.

Linux:

• Let me create a simple Java web project with default settings.

2. We are going to the project folder to check the contents of this folder:

note that there is a web folder.

3. Further:

You can create the web.xml file in this folder manually or do it using Netbeans through the context menu of the project "New → Create → Other":

Now we go to the YOURPROJECT\web\WEB-INF\ folder to see that web.xml is:

The same rules apply to the Windows operating system; check the following figures:

Here you can create web.xml:

or use Netbeans as I described above.

Answer 2

I know this so late, but I had the same problem, so here is the solution below:

To create web.xml:

• Right click on your project
• Select "New"
• Choose others
• A new file opens in the web.xml Search Filter field
• You will get the file you want to use web.xml, then click next ... then complete

(Tested on Netbean 7.4 JDK 7)

Answer 3

web.xml is optional in Java EE 6 . Thus, by default, it does not load into Netbeans . You need to manually download web.xml from Netbeans.

Answer 4

Try right-clicking on the project and choosing New Other Web Standard Deployment Descriptor (web.xml) Next Finish . Follow this and it will be created in the configuration files.

Video Tutorials: https://www.youtube.com/watch?v=UAMOeHtPwrc

Answer 5

First you need to create a servlet page, then web.xml will be generated in WEB.INF /

Answer 6

You can use contextual options in your web.xml

In your normal java class, you read these static fields.

 <?xml version="1.0" encoding="UTF-8"?> <web-app ...> ... <context-param> <description>directory where the document would be uploaded</description> <param-name>directory</param-name> <param-value>/tmp</param-value> </context-param> ... </web-app> 

And you can access this context parameter using the ServletContext.getInitParameter function.

If you use the Servlet 3.0 specification, you can use annotations ( http://docs.oracle.com/javaee/6/api/javax/servlet/annotation/package-summary.html ). I think @WebInitParam is what you are looking for.