log * n is the iterative logarithm , which for large n is defined as
log* n = 1 + log*(log n)
Therefore, log * (log n) = (log * n) - 1, since log * is the number of times you need to apply the log to a value before it reaches some fixed constant (usually 1). Running another log at first simply removes one step from the process.
Therefore, log (log * n) will be much smaller than log * (log n) = log * n - 1, since log x <x - 1 for any sufficiently large x.
Hope this helps!
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