Display decimal places in two digits, if only an integer

Question

Multiplication of two numbers

$(document).ready(function () { $("#input1, #input2").change(function () { var num = parseFloat($("#input1").val()) * parseFloat($("#input2").val()); if (num % 1 != 0) { num = Math.floor(num * 100) / 100; } else { num = parseInt(num); } $("#input3").val(num); }); }); 

• If the result is an integer of 10, it is written as 10. This is normal for me.
• If the result is 10.01, it is written as 10.01. This is normal for me.

• But if the result is 10.10, it is written as 10.1 instead of 10.10.

  How to display “always” two digits only if there are any decimal places?

Answer 1

Try the following:

http://jsfiddle.net/qjmve/

 $(document).ready(function () { $("#input1, #input2").change(function () { var num = parseFloat($("#input1").val()) * parseFloat($("#input2").val()); if (num != parseInt(num)) num = num.toFixed(2); $("#input3").val(num); }); }); 

Answer 2

Use the toFixed () function for decimal numbers.

 if(num.toString().indexOf('.') != -1) num = num.toFixed(2);