Send request parameters when invoking the command line PHP script through the command line

Question

When you run a PHP script through a browser, it looks something like

http://somewebsite.com/yourscript?param1=val1&param2=val2. 

I am trying to do the same through the command line without rewriting the script to accept argv instead of $_REQUEST . Is there a way to do something like this:

 php yourscript.php?param1=val1&param2=val2 

so that the displayed parameters are displayed in the $_REQUEST variable?

Answer 1

No, there is no easy way to achieve this. The web server will split the query string and pass it to the PHP interpreter, which will then store it in the $_REQUEST .

If you run from the command line and want to accept similar parameters, you will have to disassemble them yourself. The command line has a completely different syntax for passing parameters than HTTP. You might want to learn getopt .

For brute force approach that doesn't take user errors into account, you can try this snippet:

 <?php foreach( $argv as $argument ) { if( $argument == $argv[ 0 ] ) continue; $pair = explode( "=", $argument ); $variableName = substr( $pair[ 0 ], 2 ); $variableValue = $pair[ 1 ]; echo $variableName . " = " . $variableValue . "\n"; // Optionally store the variable in $_REQUEST $_REQUEST[ $variableName ] = $variableValue; } 

Use it as follows:

 $ php test.php --param1=val1 --param2=val2 param1 = val1 param2 = val2 

Answer 2

If you do not want to change the startup script, you can specify options using the -B option to specify the code to run before the input file. But in this case, you should also add the -F tag to indicate your input file:

 php -B "\$_REQUEST = array('param1' => 'val1', 'param2' => 'val2');" -F yourscript.php 

Answer 3

I cannot take advantage of this, but I accepted this in my bootstrap file:

 // Concatenate and parse string into $_REQUEST if (php_sapi_name() === 'cli') { parse_str(implode('&', array_slice($argv, 1)), $_REQUEST); } 

After executing the PHP file from the command line:

 php yourscript.php param1=val1 param2=val2 

The above will insert the keys and values ​​into $ _REQUEST for later searches.

Answer 4

I wrote a short function to handle this situation - if the command line arguments are present and the $ _REQUEST array is empty (i.e. when you run the script from the command line and not through the web interface), it looks for command line arguments in key = value pairs ,

 Argv2Request($argv); print_r($_REQUEST); function Argv2Request($argv) { /* When $_REQUEST is empty and $argv is defined, interpret $argv[1]...$argv[n] as key => value pairs and load them into the $_REQUEST array This allows the php command line to subsitute for GET/POST values, eg PHP .php animal=fish color=red number=1 has_car=true has_star=false */ if ($argv !== NULL && sizeof($_REQUEST) == 0) { $argv0 = array_shift($argv); // first arg is different and is not needed foreach ($argv as $pair) { list ($k, $v) = split("=", $pair); $_REQUEST[$k] = $v; } } } 

An example is given in a comment on a function presented in a comment on a function:

 PHP .php animal=fish color=red number=1 has_car=true has_star=false 

which gives an output:

 Array ( [animal] => fish [color] => red [number] => 1 [has_car] => true [has_star] => false )