I have a function that returns HTML code that retrieves and uses another file. However, the code is returned in one large paragraph, and I need it to be split into the appropriate lines. It's easy enough to print, but I need to return it in such a way that the next file picks it up.
Exit right now:
'<abbr title = 6 style="font-size: 800%">spam</abbr> <abbr title = 5 style="font-size: 800%">page</abbr> <abbr title = 4 style="font-size: 800%">penguin</abbr> <abbr title = 2 style="font-size: 800%">stem</abbr> <abbr title = 1 style="font-size: 800%">has</abbr> <abbr title = 1 style="font-size: 800%">love</abbr> <abbr title = 1 style="font-size: 800%">these</abbr> <abbr title = 1 style="font-size: 800%">spamming</abbr> <abbr title = 1 style="font-size: 800%">spammer</abbr> <abbr title = 1 style="font-size: 800%">your</abbr> <abbr title = 1 style="font-size: 800%">webpage</abbr> <abbr title = 1 style="font-size: 800%">program</abbr> <abbr title = 1 style="font-size: 800%">stemming</abbr> <abbr title = 1 style="font-size: 800%">stemmer</abbr> <abbr title = 1 style="font-size: 800%">were</abbr> <abbr title = 1 style="font-size: 800%">word</abbr> <abbr title = 1 style="font-size: 1600.0%">by</abbr> '
Required Conclusion:
<abbr title = 6 style="font-size: 800%">spam</abbr>
<abbr title = 5 style="font-size: 800%">page</abbr>
<abbr title = 4 style="font-size: 800%">penguin</abbr>
etc.....
Here is the function I'm using:
def mtcURL(URL): a = getURL(URL) COUNT = a[0] WORD = a[1] NUMBER = 800 i = 0 all_lines = "" while i < len(a[1]): if i == len(COUNT)-1: ratio = COUNT[i] / 2 NUMBER = NUMBER / (ratio) else: try: ratio = COUNT[i]/COUNT[i+1] except IndexError: pass first = '<abbr title = ' second = 'style="font-size: ' third = '%">' fourth = '</abbr> ' htmlLine = first + str(COUNT[i])+ ' ' + second + str(NUMBER)+ third + WORD[i] + fourth all_lines += htmlLine i += 1 return all_lines
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