Bash parameter separator

Question

I am trying to get 1:2:3:4:5:6:7:8:9:10 using parameter extension {1..10} and pattern matching:

 $ var=$(echo {1..10}) $ echo ${var// /:} 1:2:3:4:5:6:7:8:9:10 

Is there a more elegant way (single line) for this?

Answer 1

Agreeing with @choroba's comment on elegance, here are some other contemplative things:

 # seq is a gnu core utility seq 1 10 | paste -sd: # Or: seq -s: 1 10 # {1..10} is bash-specific printf "%d\n" {1..10} | paste -sd: # posix compliant yes | head -n10 | grep -n . | cut -d: -f1 | paste -sd: 

Answer 2

Elegance in the eye of the beholder:

 ( set {1..10} ; IFS=: ; echo "$*" ) 

Answer 3

Another possibility:

 echo {1..9}: 10 | tr -d ' '