I am just trying to open open in Python using bsddb, but encountering the following error. Any ideas? If not, is there a way to get a more detailed error message for debugging, getting more information will probably help me figure it out a bit. The error code without special details, of course, does not help much.
DBInvalidArgError: (22, 'Invalid argument')
A source:
import bsddb, bsddb.db ... try: e = bsddb.db.DBEnv() e.open('/mydir', bsddb.db.DB_CREATE | bsddb.db.DB_INIT_MPOOL) ...
Additional Information: In / mydir I have a DB_CONFIG file:
set_data_dir /mydir/current_data
Update: I think I'm here because it has something to do with the bsddb and bsddb.db versions:
> $python > Python 2.5... > import bsddb, bsddb.db > print bsddb.__version__, bsddb.db.version() > 4.4.5 (4, 2, 52) > bsddb.db.DBEnv().open('/mydir/') > bsddb.db.DBInvalidArgError: (22, 'Invalid argument') > $python2.6 > Python 2.6.6... > import bsddb, bsddb.db > print bsddb.__version__, bsddb.db.version() > 4.7.3 (4, 7, 25) > bsddb.db.DBEnv().open('/mydir/') >
There are no errors if I launched it using python2.6.
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