Dynamic arguments in php function

Question

Possible duplicate:
Does PHP get all arguments as an array?

Well,

In java, I can do this (pseudo code):

public hello( String..args ){ value1 = args[0] value2 = args[1] ... valueN = arg[n]; } 

and then:

 hello('first', 'second', 'no', 'matter', 'the', 'size'); 

Something like this in php?

EDIT

Now I can pass the array as hello(array(bla, bla)) , but there may be a method described above, right?

Answer 1

See func_get_args :

 function foo() { $numArgs = func_num_args(); echo 'Number of arguments:' . $numArgs . "\n"; if ($numArgs >= 2) { echo 'Second argument is: ' . func_get_arg(1) . "\n"; } $args = func_get_args(); foreach ($args as $index => $arg) { echo 'Argument' . $index . ' is ' . $arg . "\n"; unset($args[$index]); } } foo(1, 2, 3); 

EDIT 1

When you call foo(17, 20, 31) func_get_args() , you don't know that the first argument is the $first variable, for example. When you know what each numerical index is, you can do this (or the like):

 function bar() { list($first, $second, $third) = func_get_args(); return $first + $second + $third; } echo bar(10, 21, 37); // Output: 68 

If I want a specific variable, I can omit others:

 function bar() { list($first, , $third) = func_get_args(); return $first + $third; } echo bar(10, 21, 37); // Output: 47