Uploading files remotely to Selenium WebDriver using PHP

Question

I searched around StackOverflow (and other resources) on how to remotely upload files to Selenium WebDriver with PHP. I read this http://saucelabs.com/blog/index.php/2012/03/selenium-tips-uploading-files-in-remote-webdriver/ and it mentions that you need to use the setFileDetector method somehow to change the way you use the WebDriver library using work.

This should work fine if I used Ruby or Java. On the other hand, most PHP frameworks do not have this method.

Can someone tell me how to do this in PHP? In particular, I use the phpwebdriver library http://code.google.com/p/php-webdriver-bindings/

Answer 1

I was able to determine that the JsonWireProtocol for uploading the file would be /session/<sessionId>/file by checking the raw log in the SauceLabs.com blog ( https://saucelabs.com/jobs/1a408cf60af0601f49052f66fa37812c/selenium-server.log ), so I created this function to add to the php-webdriver-bindings library:

 /** * Send a file to your Remote WebDriver server * This will return the local URL of the file you uploaded, which will then * let you use sendKeys in file input elements * @params String $value - a local or remote file to send * @return String $resopnseValue - the local directory where the file resides on the remote server */ public function sendFile($value) { $file = @file_get_contents($value); if( $file === false ) { return false; } $file = base64_encode($file); $request = $this->requestURL . "/file"; $session = $this->curlInit($request); $args = array( 'file' => $file ); $postargs = json_encode($args); $this->preparePOST($session, $postargs); $response = trim(curl_exec($session)); $responseValue = $this->extractValueFromJsonResponse($response); return $responseValue; } 

Add this to the WebDriver.php file.

To use, just do something like this:

 ... $file_location = $webdriver->sendFile('http://test.com/some/file.zip'); $file_input = $webdriver->findElementBy(LocatorStrategy::id, 'uploadfile'); $file_input->sendKeys(array($file_location)); 

I hope this helps other developers who spend 3 hours finding the answer to this question.

Update:

I had to change this due to getting this error:

 Expected there to be only 1 file. There were: 0 

We hope that this will lead to Google results (I tried to find the error message on Google, and the only results that he could find were links to the source code in Google Code).

To solve this problem, I was able to deduce that the file you are sending should actually be archived. So I added the source code for using the PHP ZipArchive library. I will keep the old code for writing, but please use the new code here:

 public function sendFile($value, $file_extension = '') { $zip = new ZipArchive(); $filename_hash = sha1(time().$value); $zip_filename = "{$filename_hash}_zip.zip"; if( $zip->open($zip_filename, ZIPARCHIVE::CREATE) === false ) { echo 'WebDriver sendFile $zip->open failed\n'; return false; } $file_data = @file_get_contents($value); if( $file_data === false ) { throw new Exception('WebDriver sendFile file_get_contents failed'); } $filename = "{$filename_hash}.{$file_extension}"; if( @file_put_contents($filename, $file_data) === false ) { throw new Exception('WebDriver sendFile file_put_contents failed'); } $zip->addFile($filename, "{$filename_hash}.{$file_extension}"); $zip->close(); $zip_file = @file_get_contents($zip_filename); if( $zip_file === false ) { throw new Exception('WebDriver sendFile file_get_contents for $zip_file failed'); } $file = base64_encode($zip_file); $request = $this->requestURL . "/file"; $session = $this->curlInit($request); $args = array( 'file' => $file ); $postargs = json_encode($args); $this->preparePOST($session, $postargs); $response = trim(curl_exec($session)); return $this->extractValueFromJsonResponse($response); } 

Update:. Turns off, you need to set two parameters in the $ zip-> addFile () method. Edited the above code to reflect the changes.