Find href link content and URL in Java

Question

I want to parse this link:

<a href="http://www.google.fr">Link to google</a> 

To get two results:

 Link = "http://www.google.fr" LinkName = "Link to google" 

I really don't know how to do this, is there a library in Java to solve this problem?

Thanks in advance,

Answer 1

It will do.

 public class Parse { public static void main(String[] args) { String h = " <a href=\"http://www.google.fr\">Link to google</a>"; int n = getIndexOf(h, '"', 0); String[] a = h.substring(n).split(">"); String url = a[0].replaceAll("\"", ""); String value = a[1].replaceAll("</a", ""); System.out.println(url + " - " + value); } public static int getIndexOf(String str, char c, int n) { int pos = str.indexOf(c, 0); while (n-- > 0 && pos != -1) { pos = str.indexOf(c, pos + 1); } return pos; } } 

Answer 2

Use jsoup parser:

Example:

 File input = new File("/tmp/input.html"); Document doc = Jsoup.parse(input, "UTF-8", "http://example.com/"); Element content = doc.getElementById("content"); Elements links = content.getElementsByTag("a"); for (Element link : links) { String linkHref = link.attr("href"); String linkText = link.text(); }