Initialize an array without a signed byte using a hexadecimal number

Question

I know unsigned byte is missing in Java Then, how can I initialize an array of bytes using an integer from 0 to 255 (in hexadecimal format) ?

final byte assoc_resp_msg_int[] = new byte[] { 0xe3, 0x00, //APDU CHOICE Type(AareApdu) 0x00, 0x2c, //CHOICE.length = 44 0x00, 0x00, //result=accept 0x50, 0x79, //data-proto-id = 20601 0x00, 0x26, //data-proto-info length = 38 0x80, 0x00, 0x00, 0x00, //protocolVersion 0x80, 0x00, //encoding rules = MDER 0x80, 0x00, 0x00, 0x00, //nomenclatureVersion 0x00, 0x00, 0x00, 0x00, //functionalUnits, normal Association 0x80, 0x00, 0x00, 0x00, //systemType = sys-type-manager 0x00, 0x08, //system-id length = 8 and value (manufacturer- and device- specific) 0x88, 0x77, 0x66, 0x55, 0x44, 0x33, 0x22, 0x11, 0x00, 0x00, //Manager response to config-id is always 0 0x00, 0x00, //Manager response to data-req-mode-flags is always 0 0x00, 0x00, //data-req-init-agent-count and data-req-init-manager-count are always 0 0x00, 0x00, 0x00, 0x00, //optionList.count = 0 | optionList.length = 0 }; 

Answer 1

You should save 0x80 in bytes as follows:

 final byte assoc_resp_msg_int[] = new byte[] { (byte)0xe3, 0x00, //APDU CHOICE Type(AareApdu) 0x00, 0x2c, //CHOICE.length = 44 0x00, 0x00, //result=accept 0x50, 0x79, //data-proto-id = 20601 0x00, 0x26, (byte)0x80, ... } System.out.println(assoc_resp_msg_int[10]&0xFF); //128