How to search for executable file using python on Linux?

Question

How to search for executable file using python on Linux? Executable files do not have extensions and are located in a folder along with files with different extensions. Thanks

EDIT: what I mean by search is to get the file names of all executable files and save them in a list or tuple. Thanks

Answer 1

Do it in Python:

import os import stat executable = stat.S_IEXEC | stat.S_IXGRP | stat.S_IXOTH for filename in os.listdir('.'): if os.path.isfile(filename): st = os.stat(filename) mode = st.st_mode if mode & executable: print(filename,oct(mode)) 

Answer 2

If by request you want to list all the executables in the directory, than use the command from this SuperUser link . You can use the subprocess module to execute commands from python code.

 import shlex executables = shlex.split(r'find /dir/mydir -executable -type f') output_process = subprocess.Popen(executables,shell=True,stdout=subprocess.PIPE) 

Answer 3

The os.access () function is in some cases better than os.stat () , because it checks whether the file can be executed by you, according to the owner of the file, group and rights.

 import os for filename in os.listdir('.'): if os.path.isfile(filename) and os.access(filename, os.X_OK): print(filename)