How to replace the last character in a string with VB6?

Question

How to replace the last character in a string with VB6? I have syntax

Replace$(expression, find, replacewith[, start[, count[, compare]]]) 

but I can not find the correct use of this. I have something like

 iLength = Len(sBuild) sBuild = Replace(sBuild, "^", "ú", iLength, 1) 

This does not work, but I can not find examples on the Internet.

Thanks!

Answer 1

Try

sBuild = Left$(sBuild, iLength - 1) & "ú"

Answer 2

Another method is to use the Mid () keyword:

 Mid$(sBuild, Len(sBuild), 1) = "ú" 

This also has the advantage that you do not perform line reallocation / memory reallocation.