How to check if an array contains at least one element

Question

How to check if an array contains at least 1 element (and not just an empty array $myarray = array(); )?

Is there any way?

eg.

 if ($myarray) { } if (count($myarray)) { } if (count($myarray) > 0) { } 

Or is there a wrong way?

Answer 1

For at least 1 element, this will be:

 if (!empty($myarray)) {} 

Answer 2

Perhaps check for non-emptyness via empty() ?

The following things are considered empty:

• "(empty line)
• 0 (0 as an integer)
• 0.0 (0 as a float)
• "0" (0 as a string)
• Null
• False
• array () (empty array)
• var $ var; (declared variable, but no value in the class)

 if (!empty($myarray)) { // } 

But I'm not sure if there is one canonical way to do this; php can follow TMTOWTDI .

Answer 3

I believe if(!empty($myarray)) works too. This means that you will not run w / e if you get array([0] => '')