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Launch a GUI application on iOS 5 via the command line (jailbreak)

I believe that you could run GUI applications on jailbroken iOS devices through the command line (via SSH) by running the following command:

launch com.apple.Calculator

but this does not work on my iOS 5 device ( launch not found ).

I also tried:

 launchctl start com.apple.Calculator

but it also gives me an error ( no such process ).

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1 answer

Those launch / launchctl didn't work for me either. What was done to install the open command line utility from Cydia and just execute

 open com.apple.calculator

Notice the lowercase c in calculator, which was the bundle identifier for my calculator application.

Here is the developer's site for Cydia:

http://kramerapps.com/cydia/

This is the link to the repo site:

http://moreinfo.thebigboss.org/moreinfo/depiction.php?file=openData

Update: for iOS 6.x, this current version of open does not seem to work. See @Nate's answer to another question mentioned in the comments below.

Update 2: the open package in Cydia has been updated and now works with iOS 6.

Update 3: Here is the source for the package: https://github.com/conradev/Open . If you look at the open.m file, you will see that the SBSLaunchApplicationWithIdentifier function from the private structure SpringBoardServices is what the application actually opens.

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Source: https://habr.com/ru/post/905318/

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