This is a snapshot of the memory of a byte-addressed computer. What will be loaded into the register $16 after the lw $16, 24($17) command is lw $16, 24($17) , if the machine is big, and when Little Endian. Register $17 contains 200 .

Now, according to me, four bytes will be copied from memory (224-227) regardless of Little Endian or Big Endian, then if the machine is Big Endian, then they will be copied to the register as they are.
If the machine is Little Endian, it will be canceled and then copied to the register.
I ask you if I am mistaken in this concept.
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