Address of each character std :: string

Question

I tried to print the address of each character std::string . But I don’t understand what is happening inside with std::string , which leads to this conclusion, and for the array it gives the address, as I expected. Can someone explain what is happening?

 #include <iostream> #include <string> using namespace std; int main(){ string str = "Hello"; int a[] = {1,2,3,4,5}; for( int i=0; i<str.length(); ++i ) cout << &str[i] << endl; cout << "**************" << endl; for( int i=0; i<5; ++i ) cout << &a[i] << endl; return 0; } 

Conclusion:

 Hello ello llo lo o ************** 0x7fff5fbff950 0x7fff5fbff954 0x7fff5fbff958 0x7fff5fbff95c 0x7fff5fbff960 

Answer 1

When a std::ostream tries to print a char* , it takes a C-style string.

Before printing, put it before void* , and you get what you expect:

 cout << (void*) &str[i] << endl; 

Answer 2

or you can use old printf

 printf("\n%x",&s[i]);