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How to remove / replace ANSI color codes from a string in Javascript

I find it difficult to find a problem with the function below. The first parameter is a string containing ANSI color codes, and the second parameter is a logical one.

If the boolean value is set to false , the full text is done in a line.

If the boolean value is set to true , the loop will convert all color codes to something easier for me later.

I suspect RegExp 's problem is that for some reason it gets confused between 1, 33, and 0; 31.

 var colorReplace = function( input, replace ) { var replaceColors = { "0;31" : "{r", "1;31" : "{R", "0;32" : "{g", "1;32" : "{G", "0;33" : "{y", "1;33" : "{Y", "0;34" : "{b", "1;34" : "{B", "0;35" : "{m", "1;35" : "{M", "0;36" : "{c", "1;36" : "{C", "0;37" : "{w", "1;37" : "{W", "1;30" : "{*", "0" : "{x" }; if ( replace ) { for( k in replaceColors ) { //console.log( "\033\[" + k + "m" + replaceColors[ k ] ); var re = new RegExp( "\033\[[" + k + "]*m", "g" ); input = input.replace( re, replaceColors[ k ] ); } } else { input = input.replace( /\033\[[0-9;]*m/g, "" ); } return input; }; console.log( "abcd\033[1;32mefgh\033[1;33mijkl\033[0m" ); console.log( colorReplace( "abcd\033[1;32mefgh\033[1;33mijkl", true ) );

Actual conclusion:

enter image description here

Where should it be abcd{Gefgh{Yijkl

Does anyone know what is wrong now?

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2 answers

Your regex is wrong. It should be "\\033\\[" + k + "m" , not "\033\[[" + k + "]*m" .

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You can use octal codes in both lines and regular expressions

 x = "\033[1mHello Bold World!\033[0m\n"; x = x.replace(/\033\[[0-9;]*m/,""); print(x);
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Source: https://habr.com/ru/post/895603/

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