If I have a function that defines a lambda, will the lamda “build” every time the function is called? Should I make it static to prevent this?
void func(int x) { static auto lambda = [&x](int y) -> bool { // ... }; }
No, do not make it static, as it captures a local variable by reference.
I have no idea what the cost of building a lambda is. If you suspect this is a performance issue: benchmark.
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