If you are talking about the IEE754 variant, you can study Wikipedia IEEE754-1985 and independently develop calculations for a fully normalized number, taking into account the different sizes of the fraction and the indicator.
Forget the mark for now, it's just a bit flip.
The largest fraction is all one-bit, which for a ten-bit mantissa:
1 1 1 1 1 1 1 1 1 1 1 + - + - + - + -- + -- + -- + --- + --- + --- + ---- 2 4 8 16 32 64 128 256 512 1024 = 1024 + 512 + 256 + 128 + 64 + 32 + 16 + 8 + 4 + 2 + 1 ----------------------------------------------------- 1024
(implicit 1 plus ten bits in all-consuming fractions). This is 2047/1024 .
With respect to the exponent, the highest non-specific value (special values such as NaN or ±Inf ) for a 6-bit indicator is 2 6 -2 or 62 (range from 0 to 62).
But, since you need positive and negative indicators, you subtract 31 (offset, half the maximum non-specific value). This gives you a range of -30 to 31 (-31 can be discounted here, as it is not normalized).
Thus, the largest and smallest (most negative) values are ±(2047/1024)x2 31 or ±4292870144 .
Similarly, two near zero values have an exponent field of -30 (the minimum normalized) and a mantissa field of all zeros, which with an implicit 1 gives you 1 .
These values are ±(1)x2 -30 or ±0.000000000931322574615478515625 .
You have to print this page on Wikipedia and this answer and sit together until you understand them. I do not mind helping you here, but if you spew out my answer for homework, you will almost certainly be caught (if your teachers have any intelligence, although there is no guarantee that).
To put this answer on your own words (and therefore not plagiarize), you need to understand this.