How to remove fragment id from url?

Question

I have a line containing a link. A link often takes the form:

http://www.address.com/something#something

Is there a function in python that can remove "#something" from a link?

Answer 1

Just use split()

 >>> foo = "http://www.address.com/something#something" >>> foo = foo.split('#')[0] >>> foo 'http://www.address.com/something' >>> 

Answer 2

use urlparse.urldefrag :

 >>> urlparse.urldefrag("http://www.address.com/something#something") ('http://www.address.com/something', 'something') 

Answer 3

In python 3, the urldefrag function urldefrag now part of urllib.parse :

 from urllib.parse import urldefrag unfragmented = urldefrag("http://www.address.com/something#something") ('http://www.address.com/something', 'something') 

Answer 4

Try the following:

 >>> s="http://www.address.com/something#something" >>> s1=s.split("#")[0] >>> s1 'http://www.address.com/something' 

Answer 5

You can assign an unwanted part this way

 fixed, throwaway = urldefrag(url) 

where url is the fragmented address. This is a little better than a split. I did not check if it works faster or more efficiently.