I have a collection of news article objects that I want to display archived in a single month. I used itertools.groupbyto create a list of Python objects arranged in this way:
news_grouped = [
{'date': key, 'list': list(val)}
for key, val in groupby(obj_list,
(lambda v: datetime.datetime(v.pub_date.year,
v.pub_date.month, 1)))
]
So I have a collection like:
[{'date': datetime.datetime(2011, 1, 1, 0, 0),
'list': [<News: A January Article>, <News: Another January Article>]},
{'date': datetime.datetime(2010, 12, 1, 0, 0),
'list': [<News: Happy Xmas>]},
{'date': datetime.datetime(2010, 10, 1, 0, 0),
'list': [<News: Halloween>]},
{'date': datetime.datetime(2010, 1, 1, 0, 0),
'list': [<News: Old old old Jan 2010>]}]
I would like to populate the news_grouped collection so that it includes an entry for each month between the oldest article and today's date, and empty ones with an empty list.
I understand that I can do this by moving from the oldest date to the newest date and filling out the collection, but something about it just doesn’t quite sit with me, and I think that is also not very effective.
Is there a more elegant way to solve this? Can someone point me to one?
( Django , , python - , , )
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