How to replace all numbers with literal \ d in scala?

Question

I want to write a function to replace all numbers in a string with a literal \d. My code is:

val r = """\d""".r
val s = r.replaceAllIn("123abc", """\d""")
println(s)

I expect the result to be \d\d\dabc, but get:

dddabc

Then I change my code (line 2) to:

val s = r.replaceAllIn("123abc", """\\d""")

Now the result is correct: \d\d\dabc

But I don’t understand why the method replaceAllInconverts the string instead of using it directly?

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In my previous code was toList, now I want. I just updated a question. Thanks to everyone.

Answer 1

Just uninstall toList.

val r = """\d""".r
val list = r.replaceAllIn("123abc", """\\d""")
println(list)

String(implicitly, through WrappedString, converted to) Seq[Char]. If you call toList, you will have List[Char].

Answer 2

Scala Regex java.util.regex ( , JVM). , replaceAll Java-, :

, (\) ($) , . , , .