Confusion on CreateMutex

Question

Let it say that I call CreateMutex.

HANDLE h;
h=CreateMutex(NULL, TRUE, NULL);
waitforsingleobject(h, INFINITE);
////Random Code
ReleaseMutex(h);

Assuming I have multiple threads, does the first thread to access the createmutex function essentially block all other threads from the random code section until the mutex release is called correctly?

Answer 1

This is not so because you created an unnamed mutex (the third parameter is the name). Assuming that the sample code is executed in several threads, each thread will create a new unnamed mutex and immediately gain access to the critical section (Random Code), because they are only waiting for their mutex.

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Answer 2

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Answer 3

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Answer 4

Only if the same mutex reference is used for all threads / processes. You do not share it, you create it every time. You will need to name it so that they all get the same mutex so that your code works.