Why is the result of modulo operator (%) implicitly cast to the left side and not the right side in C #?

Question

Take the following code:

long longInteger = 42;
int normalInteger = 23;
object rem = longInteger % normalInteger;

If it remis the remainder longInteger / normalInteger, shouldn't the remainder always be left with a smaller "int" divisor? However, in C #, the code above leads to what remmatters long.

Is it safe to convert remto intwithout data loss?

int remainder = Convert.ToInt32(rem);

Answer 1

There is no overload of the modulo operator that accepts longand inttherefore intwill be converted to longto match another operand.

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Answer 2

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Answer 3

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