A string of values, separated by commas or semicolons, in a Python list

Question

I am reading a list of email addresses from a configuration file. Addresses can be separated by a comma or semicolon - for example,

[e-mail],[e-mail], [e-mail]
[e-mail];[e-mail];  [e-mail]

I also want to get rid of the blanks around email addresses.

I need to include them in a Python list as follows:

['[e-mail]', '[e-mail]', '[e-mail]']

What is the most pythonic way to do this? Thank.

Answer 1

In this case, I use the re module

>>> import re
>>> 
>>> data = "[e-mail];[e-mail];  [e-mail]"
>>> stuff = re.split(r"\s*[,;]\s*", data.strip())

Answer 2

Regular expressions are powerful and probably the way here; but for something simple like this, string methods are OK too. Here's a short solution:

[s.strip() for s in s1.replace(',', ';').split(';')]

Test output:

>>> s1 = "[e-mail],[e-mail], [e-mail]"
>>> s2 = "  [e-mail];[e-mail];  [e-mail]  "
>>> print [s.strip() for s in s1.replace(',', ';').split(';')]
['[e-mail]', '[e-mail]', '[e-mail]']
>>> print [s.strip() for s in s2.replace(',', ';').split(';')]
['[e-mail]', '[e-mail]', '[e-mail]']

Answer 3

';' ",", , , string.split:

>>> 'adjifjdasf;jdiafjodafs;jdiajof'.split(';')
['adjifjdasf', 'jdiafjodafs', 'jdiajof']

http://docs.python.org/library/stdtypes.html#str.split

EDIT. :

>>> map(str.strip, 'adjifjdasf;jdiafjodafs ; jdiajof'.split(';'))
['adjifjdasf', 'jdiafjodafs', 'jdiajof']

Answer 4

You can use string.maketrans to replace multiple delimiters with spaces in one pass

import string

data = "one  two,  three ; four "
stuff = [i for i in data.translate(string.maketrans(";,", "  ")).split()]

print stuff   # -> ['one', 'two', 'three', 'four']

Answer 5

You can do this using only Python string controls:

import string

s1 = "[e-mail],[e-mail], [e-mail]"
s2 = "[e-mail];[e-mail];  [e-mail]"

print s1.translate(string.maketrans(';',','), string.whitespace).split(',')
# ['[e-mail]', '[e-mail]', '[e-mail]']
print s2.translate(string.maketrans(';',','), string.whitespace).split(',')
# ['[e-mail]', '[e-mail]', '[e-mail]']

Answer 6

data = '''   [e-mail],[e-mail], [e-mail]  
  [e-mail];[e-mail];\t  \[e-mail]       '''

print repr(data),'\n'

import re

print re.findall('[^,\s;]+', data)

result

'   [e-mail],[e-mail], [e-mail]  \n  [e-mail];[e-mail];\t  \[e-mail]       ' 

['[e-mail]', '[e-mail]', '[e-mail]', '[e-mail]', '[e-mail]', '[e-mail]']

note the '\ n', '\ t' and '\ r' in this data

Answer 7

def gen_list(file_path):
    read= open(file_path, "r")
    split1= read.split(";")
    new_list= []
    for i in split1:
       split2 = i.split(",")
       split_list = [item.strip() for item in split2 if "@" in item]
       new_list.extend(split_list)
       return new_list

# This works for both comma and;. The number of lines can further be reduced