Following from Jay's answer , this can be made a good extension method:
public static class EnumerableExtensions
{
public static IEnumerable<T> OrderByMany<T>(this IEnumerable<T> enumerable,
params Expression<Func<T, object>>[] expressions)
{
if (expressions.Length == 1)
return enumerable.OrderBy(expressions[0].Compile());
var query = enumerable.OrderBy(expressions[0].Compile());
for (int i = 1; i < expressions.Length;i++)
{
query = query.ThenBy(expressions[i].Compile());
}
return query;
}
}
Usage becomes quite simple, given the test object:
public class Person
{
public string Name { get; set; }
public int Age { get; set; }
}
Then it is possible:
var people = new Person[]
{
new Person() {Name = "John", Age = 40},
new Person() {Name = "John", Age = 20},
new Person() {Name = "Agnes", Age = 11}
};
foreach(var per in people.OrderByMany(x => x.Name, x => x.Age))
{
Console.WriteLine("{0} Age={1}",per.Name,per.Age);
}
Conclusion:
Agnes Age=11
John Age=20
John Age=40
UPDATE
OrderByMany SortOrder, .
var query = from p
in people
order by Name, Age descending;
, , # 4, .
public enum SortOrder
{
Ascending,
Descending
}
:
public static IEnumerable<T> OrderByMany<T>(this IEnumerable<T> enumerable,
params Tuple<Expression<Func<T, object>>,SortOrder>[] expressions)
{
var query = (expressions[0].Item2 == SortOrder.Ascending)
? enumerable.OrderBy(expressions[0].Item1.Compile())
: enumerable.OrderByDescending(expressions[0].Item1.Compile());
for (int i = 1; i < expressions.Length; i++)
{
query = expressions[i].Item2 == SortOrder.Ascending
? query.ThenBy(expressions[i].Item1.Compile())
: query.ThenByDescending(expressions[i].Item1.Compile());
}
return query;
}
:
foreach (var per in people.OrderByMany(
new Tuple<Expression<Func<Person, object>>, SortOrder>(x => x.Age, SortOrder.Descending),
new Tuple<Expression<Func<Person, object>>, SortOrder>(x => x.Name, SortOrder.Ascending)))
{
Console.WriteLine("{0} Age={1}", per.Name, per.Age);
}