2 dimensional array in c #

Question

Is it possible to initialize the second dimension as dynamically significant?

Answer 1

No (since the dimensions of the C # array are fixed), but you can create an array List<T>.

Answer 2

Do you mean a gear array? Like this:

class Program
{
  public int[][] jaggedArray = {
                                 new int[]{ 1 } ,
                                 new int[]{} ,
                                 new int[]{ 1 , 2 , 3 } ,
                               } ;
}

Answer 3

. :

List<List<int>> list = new List<List<int>>();

, . , .

: "" , :

List<int>[] list = new List<int>[100]();

: , , - :

List<int>[] sVertRange = new List<int>[924];

int nH = 0;
for (int h = 315; h < 1240; h++) 
{
    for (int v = 211; v <= 660; v++) 
    {
            Color c = bmp.GetPixel(h, v);
            if (c.R > 220 && c.G < 153) 
        {
            if(sVertRange[nH] == null)
            {
                sVertRange[nH] = new List<int>();
            }

                    sVertRange[nH].Add(v);
            }
            nH++;
        }
}

Answer 4

UPDATE: , - . , Kees?

    int[][] sVertRange = {new int[924] ,new int[]{}};  
    int nH = 0;
    int nV = 0;
    for (int h = 315; h < 1240; h++) {
        for (int v = 211; v <= 660; v++) {
            Color c = bmp.GetPixel(h, v);
            if (c.R > 220 && c.G < 153) {
                sVertRange[nH][nV++] = v;
            }
        nH++;
        }
    }

Answer 5

2- #, -

int num1 = 10,num2 = 20;
Bitmap[][] matrix= new Bitmap[num1][]; 
for (int i = 0; i < num1; i++ )
     matrix[i] = new Bitmap[num2];