I am new to Java and am in the above error when using HTTPURLConnection to send multiple messages on Android. I wrote an HTTPTransport class in which I would like to have sendMessage and recvMessage methods.
public class HTTPTransport
{
private HttpURLConnection connection;
public HTTPTransport()
{
URL url = new URL("http://test.com");
connection = (HttpURLConnection) url.openConnection();
connection.setRequestMethod("POST");
connection.setDoInput(true);
connection.setDoOutput(true);
connection.setRequestProperty("Content-Type", "application/octet-stream");
connection.setRequestProperty("Accept-Encoding", "gzip");
connection.setRequestProperty("Connection", "Keep-Alive");
}
public void sendMessage(byte[] msgBuffer, long size)
{
try
{
DataOutputStream dos = new DataOutputStream(connection.getOutputStream());
dos.write(msgBuffer, 0, (int)size);
dos.flush();
dos.close();
dos.close();
}
catch( IOException e )
{
Log.e(TAG, "IOException: " + e.toString());
}
}
public byte[] recvMessage()
{
int readBufLen = 1024;
byte[] buffer = new byte[readBufLen];
int len = 0;
FileOutputStream fos = new FileOutputStream(new File("/sdcard/output.raw"));
DataInputStream dis = new DataInputStream(connection.getInputStream());
while((len = dis.read(buffer, 0, readBufLen)) > 0)
{
Log.d(TAG, "Len of recd bytes " + len + ", Byte 0 = " + buffer[0]);
fos.write(buffer, 0, len);
}
fos.close();
dis.close();
return RecdMessage;
}
}
I can send the first message using sendMessage and recvMessage. When I try to send the second, I see this error: IOException: java.net.ProtocolException: cannot open OutputStream after reading from inputStream
Please let me know how I can write this class.
Thank!
source
share