In Java, is it possible that calling the super constructor invokes the constructor in the calling class?

Question

Super constructor call definition :

[Primary.] [NonWildTypeArguments] super ( ArgumentListopt ) ;

A superconstructor call can be prefixed with an expression Primary. Example (taken from JLS):

class Outer {
    class Inner{ }
}

class ChildOfInner extends Outer.Inner {
    ChildOfInner() {
        (new Outer()).super(); // (new Outer()) is the Primary
    }
}

Is there an expression Primarythat makes a call to super () a call to the constructor of the calling class? Or does Java prevent this?

Answer 1

Is there a primary expression that makes a call to super () a call to the constructor of the calling class?

. super(), this(). Primary , .

- , (.. , ).

Edit:

OP . - , , , :

... super... .

, p, ".super", ... [] ... , p O [ ] O.

super , ( ). , super(), , , , super() - super() .

Answer 2

, , Java ( ). , , . , ( , ).

:

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