How to remove% 20 from file path?

Question

file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3

How can I convert a string like the one above to get a normal file path that I can pass to a function open()?

Answer 1

Take a look url2pathname:

import urllib2

path = urllib2.url2pathname("file:///home/ashu/Music/Collections/randomPicks/ipod%20on%20sep%2009/Coldplay-Sparks.mp3")

Answer 2

This is called unquote. Available from urllib.

import urllib
urllib.unquote('%20')