Trailing NULL in an array in C

Question

I have a simple question.
Why it is necessary to consider the terminating zero in an array of characters (or just a string), and not an array of integers. So when I want the string to contain 20 characters, I need to declare char string[21];. When I want to declare an array of integers containing 5 digits, then int digits[5];enough. What is the reason for this?

Answer 1

You do not need to interrupt the array charwith NULLif you do not want to, but when using them to represent a string, you need to do this because C uses zero-terminated strings to represent your strings. When you use functions that work with strings (for example, strlenfor the length of a string or using printfto output a string), these functions will read the data until it is encountered NULL. If not, then you are likely to encounter buffer overflows or similar problems with access violations / segmentation.

In short: how C represents string data.

Answer 2

Zero terminators are required at the end of strings (or character arrays) because:

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Answer 3

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int i = 0;
while(input[i] != '\0') {
   output(input[i]);
   i++;
}

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Answer 4

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Answer 5

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Answer 6

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Answer 7

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Answer 8

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Answer 9

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