RegEx for value Range 1 to 365

Question

What is RegEx for a range of values ​​from 1- 365

Answer 1

Not suitable for regular expression, but if you insist:

^(?:36[0-5]|3[0-5][0-9]|[12][0-9][0-9]|[1-9][0-9]|[1-9])$

This does not allow leading zeros. If you want to allow them, let me know.

The above expression may be slightly reduced to

^(?:36[0-5]|3[0-5]\d|[12]\d{2}|[1-9]\d?)$

but I believe that the first solution will be more readable. YMMV.

Answer 2

You will need to indicate the possible combinations 1-9, 10-99, 100-299, 300-359, 360-365:

^([1-9]\d?|[12]\d\d|3[0-5]\d|36[0-5])$

Answer 3

:

^(?:[1-9]\d?|[12]\d{2}|3[0-5]\d|36[0-5])$

• ^ $ .
• (? ) .
• |
• [1-9]\d?     1 to 99
• [12]\d{2}   100 - 299
• 3[0-5]\d     300 - 359
• 36 [0-5]             360 - 365

Answer 4

1 XYZ

^(?!0)(?!\d{4}$)(?![X+1-9]\d{2}$)(?!X[Y+1-9]\d$)(?!XY[Z+1-9]$)\d+$

:

• X, Y Z 9, X + 1 .. 10. , , 10, .
• , .
• 0es.

:

^(?!0)(?!\d{4}$)(?![4-9]\d{2}$)(?!3[7-9]\d$)(?!36[6-9]$)\d+$

:

(?!0\d*) - does not start with 0
(?!\d{4}$) - does not have 4 digits, i.e. between 1000 and infinity
(?![4-9]\d{2}$) - it not between 400 and 999
(?!3[7-9]\d$) - it not between 370 and 399
(?!36[6-9]$) - it not between 366 and 369

.

Answer 5

^3(6[0-5]|[0-5]\d)|[12]\d\d|[1-9]\d|[1-9]$

05 :

^3(6[0-5]|[0-5]\d)|[12]?\d?\d$

P.S.: . ToInt(), < =, > =

Answer 6

^36[0-5]|(3[0-5]|[12]?[0-9])[0-9]$

Answer 7

, PCRE-style. , , .

- :

^[1-9]|[1-9][0-9]|[1-2][0-9]{2}|3[0-5][0-9]|36[0-5]$

( ):

• 1-9.
• 10-99.
• 100-299.
• 300-359.
• 360-365.

, , . .

^[0-9]{1,3}$, , , 1 365 :

def isValidDayOtherThanLeapYear (s):
    if not s.matches ("^[0-9]{1,3}$"):
        return false
    n = s.toInteger()
    if n < 1 or n > 365:
        return false
    return true

, , , .