What is the difference between these two object initializations in java?

Question

If I use:

    HashMap<String, Integer> test = new HashMap<String, Integer>();

Or I use:

    HashMap test = new HashMap();

Is there any difference in further methods that I can apply to the test object. e.g. test.put (), test.get (), etc., if they are initialized differently.

Also, if I put something in a test object, for example:

    test.put("One", new Integer(5));
    test.put("Two", new Integer(4));
    test.put("Three", new Integer(3));

and display it as:

Set set = tokens.entrySet ();
      Iterator ik = test.iterator ();

    while(ik.hasNext()){
      Map.Entry me = (Map.Entry)ik.next();
      System.out.println(me.getKey() + " : " + me.getValue() );

The result is not sorted, restul:

Three: 3 One: 5 Two: 1

What rule does he follow? Is this normal output behavior randomly displayed?

Answer 1

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Answer 2

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, Java Generics.

Answer 3

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Answer 4

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Answer 5

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