Put the numbers on the circle like a clock. Now create a logical cross, say, at 12, 3, 6, and 9 oclock. Put 12 on the first number. Now find which numbers will be closest to oclock 3, 6, and 9, and write down the sum of these three numbers next to the first number.
, - 12 - , . , , 12- .
, 12 , 3 oclock, . , , .
R N , . "" - R/N , , , . , 6 , 6- , 60 , 90 . , . : R N.
Perl, Ive - .:)