Clone a <table> with specific rows and columns

Question

I try my best to work with the following functionality, I need to clone the table, but I only need the first 'td'of each row and remove the title. Can someone point me in the right direction, I have tried several things now, but not joy. Tried a few things, such as:

$('#tableMembers').find('tr').find('td:not(first)').remove();

Which obviously didn't work.

Answer 1

First, you must first clone, otherwise you delete the original.

var newTable$ = $('#tableMembers').clone().find('tr').find('td:gt(0)').remove();
$('#someTargetLocation').append(newTable$);

Something in this direction should do it. td: gt (0) will find all td elements that are not the first in their row.

find ('tr') , td: gt (0) . find ('tr') find ('td: gt (0)') tr , .

Answer 2

.

$('#tableMembers').clone().prependTo(....).find('td:first-child').remove();