Getting all subgroups with regex

Question

Given the line:

 © 2010 Women’s Flat Track Derby Association (WFTDA) 

I want to:

2010 -- Women -- Flat
Women -- Flat -- Track
Track -- Derby -- Association

I am using regex:

([a-zA-Z]+)\s([A-Z][a-z]*)\s([a-zA-Z]+)

He returns only:

s -- Flat -- Track

Answer 1

This problem is not easy, but to understand why you need to understand how the regular expression mechanism in your string works.

[a-z]{3} ( 3 a z) abcdef. ( a) , a [a-z], . , b [a-z] . , , c , ( d) abc .

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b abc, bcd . , , .

---

, lookaheads , :

var str = "2010 Women Flat Track Derby Association",
    regex = /([a-z0-9']+)(?=\s+([a-z0-9']+)\s+([a-z0-9']+))/ig;

while (match = regex.exec(str))
{
    var group1 = match[1], group2 = match[2], group3 = match[3];
    document.write("Found match: " + group1 + " -- " + group2 + " -- " + group3 + "<br />\n");
}

:

2010 -- Women -- Flat
Women -- Flat -- Track
Flat -- Track -- Derby
Track -- Derby -- Association

. http://jsfiddle.net/jRgXm/.

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Answer 2

, , , ...

([A-Z0-9][\w’]+)\s([A-Z][\w]+)\s([A-Z][\w]+)

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