Unix Cut Operation

Question

I have a line like this:

uid=2560(jdihenia) gid=1000(undergrad)

I want to just get the part undergradfor var1 variable. Therefore, I used the command

var1=`echo "uid=2560(jdihenia) gid=1000(undergrad)" | cut -d "(" -f 3`

but it will assign the value undergrad)in to in var1. Could you tell me how can I get only the part undergradin var1 variable?

Answer 1

If you want the literal text "undergrad" in brackets, this should work:

cut -d "(" -f 2 <text> | cut -d ")" -f 1

or equivalent

echo <text> | cut -d "(" -f 2 | cut -d ")" -f 1

Answer 2

If this line matters id, you can just call id -gn.

Answer 3

var1=$(cmd |sed 's/.*(\([^)]*\))/\1/')

Answer 4

var1="uid=2560(jdihenia) gid=1000(undergrad)"
var1=${var1#*\(*\(}
var1=${var1%%\)*}

Answer 5

echo "$str" | awk -F'[()]' '{print $4}'

Answer 6

var1=$( echo "uid=2560(jdihenia) gid=1000(undergrad)" | grep -Po 'gid=.*\(\K.*(?=\))')