Calling the base class move ctor [C ++ 0x]

Question

What is the correct way to call the move ctor base class?

this (works in MSVC2010, but not in CBuilder2010):

struct Foo
{
    Foo(Foo&& other) { }
};

struct Bar : public Foo
{
    Bar(Bar&& other) : Foo((Foo&&)other) { }
};

or (works in CBuilder2010, but not in MSVC2010):

struct Foo
{
    Foo(Foo&& other) { }
};

struct Bar : public Foo
{
    Bar(Bar&& other) : Foo(&other) { }
};

or are they both wrong? If so, what is the correct way (in terms of what is specified in C ++ 0x standards)?

Note. I cannot figure out how to make it work in CBuilderXE (both versions do not work).

Answer 1

The first option seems logical, although I would call it std::forward<Bar>(other).

I have no idea why CBuilder thinks type &otheris equal Bar&&, not Bar*.

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Answer 2

, , , . std::forward<Bar>(other) - - , .