Xslt - adding </tr> <tr> of each n node?

Question

I found an elegant solution for this problem: xsl for-each: add code block every n lines?

I would like to understand the xslt code, and I was wondering if you can help me figure this out by looking at the link above.

Mostly there are 3 <xsl:template>. For me, the first two are enough to achieve the goal. However, I tried only 2 <xsl:template>and it does not work. In short, a third is required. There he is:

<xsl:template match="gallery[not(position() mod 6 = 1)]"/>

The second template has a mode, while the latter does not.

I have no idea when the latter is being executed. Could you help me figure it out?

Thank you for your help.

Hi,

Rolling

Answer 1

, . , , , :

<xsl:stylesheet version="1.0" 
 xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> 
 <xsl:output omit-xml-declaration="yes" indent="yes"/> 
 <xsl:strip-space elements="*"/> 

XSLT . 6k + 1th gallery. tr, gallery 5. ( "proc" ), , XSLT .

 <xsl:template match="gallery[position() mod 6 = 1]"> 
  <tr> 
   <xsl:apply-templates mode="proc" 
        select=".|following-sibling::gallery[not(position() > 5)]" 
   /> 
  </tr> 
 </xsl:template> 

"proc" gallery 6, .

<xsl:template match="gallery" mode="proc"> 
  <td> 
    <img src="{gallery-image-location}" alt="{gallery-image-alt}"/> 
  </td> 
 </xsl:template> 

XSLT gallery, 6k + 1 ( 6-). - , "proc" .

 <xsl:template match="gallery[not(position() mod 6 = 1)]"/> 
</xsl:stylesheet> 

XSLT, .

Answer 2

1 7, . 2,3,4,5,6,8 9, .. , -.