Call the same instance of the program?

Question

I am creating a C program that is called from a shell script when a specific event occurs. Program C receives an argument from a shell script as follows:

> ./c-program.bin HELLO

Now the C program runs until it receives a specific character as an argument. The problem is that if a second event occurs, and the C program is now called like this:

./c-program.bin WORLD

Then this is a new instance of the program that starts, which does not know anything about the line from the first event. What I would like to achieve looks something like this:

[EVENT0] ./c-program.bin HELLO
[EVENT1] ./c-program.bin WORLD
[EVENT2] ./c-program.bin *

c-program output:

HELLO WORLD

Any ideas on how to have only one instance of the program? The platform is Linux. Thus, the project is in the planning phase, I do not have a specific code yet, I first try to deal with various problems.

Answer 1

, , , script

script , '*', c.

, script script, :

secondscript HELLO
secondscript WORLD
secondscript *

script *, c

./c-program.bin HELLO WORLD

---

, . script 10 . /script:

passedstring = args[0]

if passedstring = "*"
    string cache = readcontents(cachefile)
    call c program passing cache
    clearcontents(cachefile)
else
    append(cachefile, passedstring)   

dancin, , , :)

Answer 2

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Answer 3

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- unix , mysql.sock.

Answer 4

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Answer 5

, , . , , "" - , .

:

• fifo . , , fifo, , *, fifo, *.
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• *, fifo , , - *.