can anyone tell me how to randomly access a file beyond 2 GB using the Android SDK. I tried to find position> 2147483647 and received an exception: "The value is too large for a particular data type." This is odd because the search command parameter is of type "long". See the sample code for more details:
RandomAccessFile BigFile; BigFile = new RandomAccessFile(sMyFileName, "r"); BigFile.seek(2147483648); --> Exception
Thanks for any help, Michael
native/IO (system). / . - EOVERFLOW ( " " ). lseek, , .
: 64- "":-) JRE , IIRC. , Android.
: FAT32, 2 , , Android 2.x( // / IO lib - - " " ).
Source: https://habr.com/ru/post/1769598/More articles:Best / common practice for delimiting values in C when printing them - cКак организовать .NET-решения, проекты и системные папки для нескольких приложений? - .netWhy does changing a UIScrollView frame change the scope of its subzones? - iphoneIs it better to generate html for the ajax function in the JS handler or in the ajax PHP function? - jqueryHow to cut and save a rectangle from an image? - javaRaw data or pre-calculated values in the database? - performanceCreate a new message with default signature using Exchange Web Services - c #C # handling keystrokes - c #https://translate.googleusercontent.com/translate_c?depth=1&pto=aue&rurl=translate.google.com&sl=ru&sp=nmt4&tl=en&u=https://fooobar.com/questions/1769602/how-can-i-wrap-lines-to-45-characters-in-a-perl-program&usg=ALkJrhhZCl-MIM7K0KmS7lLmHvy8sPJHBgSpring / Spring Security 3.0.x thread - springAll Articles