Run unix command in php

Question

In php, I need to find if a directory exists. IF it does not exist (I will show a hyperlink for this using the name dirname)

Here is an example where I need help.
dir_name is the name of the directory

$url = system(~'ls -d /home/myapps/rel/".$dir_name"');
        echo $url;(this does not work)
        if(preg_match("/No such/",$url)) {
                echo'Ther is no match'
        }
        else{
        }

In my code, the if block is never executed. (it should be executed if the directory does not exist); (

Answer 1

Why aren't you using is_dir()?

http://php.net/manual/en/function.is-dir.php

Answer 2

As others said, the is_dirright way.

I will indicate why your existing program is not working. This will be useful in cases where you want to run an external command and then analyze its output.

• ~ system.

• . - :

  system('ls -d /home/myapps/rel/'.$dir_name);

  system("ls -d /home/myapps/rel/$dir_name");

• , , ls "....not found" stderr, stdout, stdout. stderr of stdout :

  system("ls -d /home/myapps/rel/$dir_name 2>&1");

• , system last line. , , / system , exec, . - :

  exec("ls -d /home/myapps/rel/$dir_name 2>&1",$output_arr);
  err $output_arr

, ( ) $url, "No such".

:

• bash , . /foo/bar not found, .
• , $dir_name No such ( ) .

Answer 3

http://php.net/manual/en/function.file-exists.php

bool file_exists  ( string $filename  )

Returns true if a file or directory exists. If you then need to find out if its directory or file is usingis_dir()