How to create a checksum for an XML file in Java

Question

I need to create a checksum for an XML file in Java. Primary requirements:

• The order of the elements matters
• The name-value attribute pair is important, but the order of the attributes is NOT:
• Ignore all spaces and comments

Anyone can provide any hint or sample code?

Thanks Mark

Answer 1

Method 1. Use XSLT to normalize the document.

Essentially, you should use XSLT to normalize XML documents so that equivalent documents go into the same document. Conversion:

• Keeping items in order
• Order attributes of each element (e.g. alphabetize based on attribute name)

.

:

• XSLT - https://stackoverflow.com/questions/1858345/xsltwhich-is-the-best-tutorial-you-would-like-to-recommend
• - XSL, XML
• - XSL
• normalize-space() - xpath normalize-space() ?

2. DOM

• DOM- DOM
• DOM .
• XML .

3. SAX StAX

DOM, SAX StAX XML //, , ///value/etc .

Answer 2

API- Java Digital Signature API:

API Java XML

Answer 3

W3C 'c14n'. + . . , libarry implemntation