Doubt in malloc. C (Linux)

Question

In the following code, what's the point buf = malloc(n * sizeof(char));

n * sizeof (char) is necessary, if so .. please specify.

int n;

char* buf;

fstat(fd, &fs);

n = fs.st_size;

buf = malloc(n * sizeof(char));

EDIT1 And what if I write (n * sizeof (double))

Answer 1

The function mallocallocates bytes and takes as input the number of bytes that you would like to allocate. The operator sizeofreturns the number of bytes for this type. In this case, a charis 1 byte, but in the case int, most likely 4 bytes, or doublemost likely 8 bytes. An expression n * sizeof(char)converts a number charto the number of bytes desired.

, char, , , , , , , .

, , n char buf .

Answer 2

ISO byte , char.

sizeof(char) malloc